JP Math Lab

7-Day Course

Master Linear Functions in 7 Days

7日間で一次関数を完全攻略

Go from "I sort of get it" to "I can solve any problem on my own." Connect concepts, graphs, and real-world applications in 7 structured days.

Target: Junior High 2 / Overseas Japanese students

1

Turning Change into Equations

Free

「変化」を式にする

Understand that y = ax + b describes a constant rate of change. The slope (a) is how much y changes when x increases by 1. The y-intercept (b) is where the story begins.

Concept

A linear function describes a **constant rate of change**.

If x increases by 1, y always changes by the same amount — that amount is the **slope (a)**.

Where the line crosses the y-axis is the **y-intercept (b)**.

Think of it like a taxi meter: - The base fare is **b** (the y-intercept) - Every kilometer costs **a** yen more (the slope) - Total fare: y = ax + b

Examples

A taxi charges a base fare of 500 yen, plus 100 yen per kilometer. Express the total fare y for x kilometers.

y = 100x + 500

The rate of change is 100 yen/km (slope a = 100). The starting cost is 500 yen (intercept b = 500). So the equation is y = 100x + 500.

For y = 2x + 3, find the value of y when x = 4.

Substitute x = 4 into y = 2x + 3:
y = 2(4) + 3
y = 8 + 3
y = 11

We replace x with 4 and compute step by step. Each step should show the calculation clearly.

Write the equation of a linear function with slope -1 and y-intercept 5.

y = -x + 5

Slope a = -1, intercept b = 5. Plug directly into y = ax + b.

2

Reading, Drawing & Creating Graphs

Free

グラフを「読む・書く・作る」

Convert between equations and graphs in both directions. Given an equation, draw the graph. Given a graph, write the equation.

Concept

Two key skills:

**1. Equation → Graph** Start at the y-intercept (b), then use the slope (a) to find more points.

**2. Graph → Equation** Find the slope from two points, then find b from the y-axis crossing.

**Slope formula:** a = (y₂ - y₁) / (x₂ - x₁)

Example: Points (1, 5) and (3, 9) a = (9 - 5) / (3 - 1) = 4 / 2 = 2

Examples

Draw the graph of y = -2x + 4. Identify the y-intercept and one other point.

y-intercept: (0, 4)
When x = 1: y = -2(1) + 4 = 2 → point (1, 2)
When x = 2: y = -2(2) + 4 = 0 → point (2, 0)
Plot these points and draw a straight line through them.

Start at b = 4 on the y-axis. The slope is -2, so for every 1 step right, go 2 steps down.

Find the equation of the line passing through (0, 3) and (2, 7).

Let the equation be y = ax + b.

Find the slope:
a = (7 - 3) / (2 - 0) = 4 / 2 = 2

Since the line passes through (0, 3), b = 3.

Therefore y = 2x + 3

When one point is on the y-axis (x = 0), b is simply the y-coordinate of that point.

Find the equation of the line passing through (-1, 0) and (0, 2).

Let the equation be y = ax + b.

Find the slope:
a = (2 - 0) / (0 - (-1)) = 2 / 1 = 2

From point (0, 2): b = 2

Therefore y = 2x + 2

The point (0, 2) tells us b = 2 directly. Then we just need the slope.

3

Building Equations from Conditions

式の作り方 — 2点・傾き+1点

Learn to derive the equation from any set of conditions: slope + point, two points, or graph readings.

4

Mixed Practice — 10 Problems

実践演習10問

Cross-pattern problems covering equation→graph, graph→equation, two-point derivation, and word problems. Target: 20 minutes.

5

Word Problems — Real World to Equations

文章題を式に変換する

Master the framework: identify x and y, find the rate of change (slope), find the starting point (intercept), build y = ax + b.

6

Comprehensive Test

総合テスト

15 problems in 30 minutes. Section A: basics (30pts), Section B: graphs (30pts), Section C: word problems (40pts).

7

Solutions & Next Steps

解説+次のステップ

Detailed solutions for all Day 6 problems. Common mistake patterns. Bridge to simultaneous equations and quadratic functions.