7日間コース
Master 3D Geometry in 7 Days
Understand spatial relationships, nets, projections, and calculate volumes and surface areas of prisms, cylinders, pyramids, cones, and spheres.
対象: Junior High 1 / Overseas Japanese students
Concepts & Worked Examples
Planes, lines in space, nets, projections, volumes, surface areas, and spheres.
平面を決定する条件:
2直線の位置関係:
立体を広げた図。表面積の計算に使う。
角柱・円柱: V = 底面積 × 高さ = Sh 角錐・円錐: V = (1/3) × 底面積 × 高さ = (1/3)Sh
例:円柱 半径3cm、高さ5cm → V = π(9)(5) = 45π cm³ 例:円錐 半径3cm、高さ5cm → V = (1/3)π(9)(5) = 15π cm³
円柱: 2πr² + 2πrh 例:r=3, h=5 → 18π + 30π = 48π cm²
円錐: πr² + πrl(母線 l) 例:r=3, l=5 → 9π + 15π = 24π cm²
体積: V = (4/3)πr³ 表面積: S = 4πr²
例:半径6cm → V = 288π cm³、S = 144π cm²
A cylinder has radius 4 cm and height 10 cm. Find its volume and surface area.
解答
V = π(16)(10) = 160π cm³ SA = 2π(16) + 2π(4)(10) = 32π + 80π = 112π cm²
Apply V = πr²h and SA = 2πr² + 2πrh.
A cone has radius 6 cm and slant height 10 cm. Find the surface area.
解答
SA = π(36) + π(6)(10) = 36π + 60π = 96π cm²
SA = πr² (base) + πrl (lateral surface).
A sphere has radius 3 cm. Find its volume.
解答
V = (4/3)π(27) = 36π cm³
V = (4/3)πr³ = (4/3)π(3³).
Basic Practice
Practice volume, surface area, and spatial relationship questions.
空間図形の計算を練習。
Volume of a rectangular prism 3×4×5 cm.
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答え
60 cm³
A cone has base radius 3 and height 4. Find V.
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答え
V = (1/3)π(9)(4) = 12π cm³
Surface area of a cube with side 5 cm.
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答え
6 × 25 = 150 cm²
Two lines in space that are not parallel and do not intersect are called?
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答え
Skew lines (ねじれの位置)
A sphere has surface area 100π cm². Find the radius.
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答え
4πr² = 100π → r² = 25 → r = 5 cm
Standard Practice
Volume/SA of various solids, nets. ★2-3.
Pattern Practice
All 3D geometry patterns. ★2-3.
Applied Practice
Composite solids and real-world volume problems. ★3-4.
Advanced Practice
Complex solids, rotational bodies. ★4-5.
Final Test & Bridge to Next
Comprehensive test. Preview of angles and congruence.